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alan2525
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Joined: 02 Feb 2008
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Location: Essex, UK
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 Posted: Sun Jun 15, 2008 5:46 pm Post subject: Workshop math for setting up a ball turning attachment |
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A picture paints 1000 words:
I'm turning some ball ended handrail brackets and need to work out the value of "z" where "x" and "y" are known dimensions!
What would be the formula for working it out? Sorry for the maths! I'm not bright enough to work it out though! I could just use a cad drawing and take the dimension from that! |
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GUTMACH
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Joined: 21 May 2008
Posts: 107
Location: Arizona
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| Posted: Sun Jun 15, 2008 6:32 pm Post subject: Ball Turning |
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Alan,
Why isn't dimension 'X' and 'Z' the same.
Or go to this site, and have a look at their concept,
[urlhttp://www.statecollegecentral.com/metallathe/MLA-13.html[/url]
Just a start...
Wayde |
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johnreid
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| Posted: Sun Jun 15, 2008 7:00 pm Post subject: |
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A teacher explained it to me this way
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bigal
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Joined: 07 May 2008
Posts: 448
Location: MA. USA
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| Posted: Mon Jun 16, 2008 2:02 pm Post subject: |
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| johnreid wrote: | A teacher explained it to me this way
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You've got to be kidding 
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alan2525
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Location: Essex, UK
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| Posted: Mon Jun 16, 2008 2:34 pm Post subject: |
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Thanks for the prompt replies! I knew this would be a great place to ask for help! Now I just need how to find the sideways number 5 on my keyboard...is it a letter of the greek alphabet?
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Stilldrillin
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Location: Staveley, Derbyshire. UK
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| Posted: Mon Jun 16, 2008 2:59 pm Post subject: |
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Pythagoras.... Innit?
Square on the hypoteneuse = sum of squares on other 2 sides.
Centre of ball, to intersection with o/d of shaft (y) = half of x (hypoteneuse).
Vertical from c/l of shaft, to intersection = half of y (adjacent)
Horizontal = hyp squared - adj squared.
Add half of x for your answer......
Gimme some dimensions, and I can work it out quicker than try to explain......... 
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Last edited by Stilldrillin on Mon Jun 16, 2008 4:07 pm; edited 2 times in total |
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tmuir
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Location: Western Australia
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| Posted: Mon Jun 16, 2008 3:00 pm Post subject: |
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| alan2525 wrote: | Thanks for the prompt replies! I knew this would be a great place to ask for help! Now I just need how to find the sideways number 5 on my keyboard...is it a letter of the greek alphabet?
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Its right besides the 'anykey'
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James
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Location: Nr. Gainsborough, Lincolnshire, England.
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| Posted: Mon Jun 16, 2008 3:33 pm Post subject: |
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Ahhh maths!! 
Pythagerous or whatever his name is, ain't that a2 + b2 = c2
(2 meaning squared)
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Stilldrillin
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| Posted: Mon Jun 16, 2008 4:03 pm Post subject: |
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Yep!
You work it out for him.......
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David.
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James
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| Posted: Mon Jun 16, 2008 4:11 pm Post subject: |
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LMFAO I fail maths, but everything else I excel at
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alan2525
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Location: Essex, UK
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| Posted: Mon Jun 16, 2008 4:30 pm Post subject: |
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| tmuir wrote: | | alan2525 wrote: | Thanks for the prompt replies! I knew this would be a great place to ask for help! Now I just need how to find the sideways number 5 on my keyboard...is it a letter of the greek alphabet?
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Its right besides the 'anykey' |
Those crazy Australian Keyboards! But do you have a "panic" button?
I have an "FlOCK" key too - it looks a bit dodgy though as the lettering is starting to wear off a bit!  |
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Stilldrillin
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| Posted: Mon Jun 16, 2008 4:40 pm Post subject: |
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Dimensions?
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David.
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alan2525
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Joined: 02 Feb 2008
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Location: Essex, UK
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| Posted: Mon Jun 16, 2008 6:05 pm Post subject: |
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| Stilldrillin wrote: | Pythagoras.... Innit?
Square on the hypoteneuse = sum of squares on other 2 sides.
Centre of ball, to intersection with o/d of shaft (y) = half of x (hypoteneuse).
Vertical from c/l of shaft, to intersection = half of y (adjacent)
Horizontal = hyp squared - adj squared.
Add half of x for your answer......
Gimme some dimensions, and I can work it out quicker than try to explain......... |
If
x=4
y=1.8
Calculate the value of z |
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Stilldrillin
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| Posted: Mon Jun 16, 2008 6:13 pm Post subject: |
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3.786
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David.
All those days which have come and gone......
I didn`t know that was life! |
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James
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| Posted: Mon Jun 16, 2008 9:42 pm Post subject: |
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Bloody hell that bloke, our David, is reet clever like!
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